Linked Lists in Python
pythonwife.com › linked-lists-in-pythonHow to Sort a Linked List in Alphabetical Order in Python? def sort(self): Ahead = self.Node(0) Dhead = self.Node(0) self.splitList(Ahead, Dhead) Ahead = Ahead.next Dhead = Dhead.next Dhead = self.reverseList(Dhead) self.head = self.mergeList(Ahead, Dhead) def reverseList(self, Dhead): current = Dhead prev = None while current != None: self._next = current.next current.next = prev prev = current current = self._next Dhead = prev return Dhead def mergeList(self, head1, head2): if head1 ...
Program to sort a given linked list into ascending order in ...
www.tutorialspoint.com › program-to-sort-a-givenNov 26, 2020 · We have to sort the list into ascending order. So, if the input is like [5, 8, 4, 1, 5, 6, 3], then the output will be [1, 3, 4, 5, 5, 6, 8, ] To solve this, we will follow these steps: values := a new list; head := node; while node is not null, do. insert value of node at the end of values; node := next of node; sort the list values
data structures - Sorted Linked List in Python - Stack Overflow
stackoverflow.com › questions › 19217647May 10, 2016 · class Node: def __init__(self, data, _next=None): self.data = data self.next = _next def main(): nodes = [] num = int(input("Enter number: ")) while num != -1: nodes.append(Node(num)) num = int(input("Enter number: ")) # If list is empty then just end function if len(nodes) == 0: return # Let python do the sorting nodes = sorted(nodes, key=lambda node: node.data) # Link the nodes together and print them while you're at it for i in range(len(nodes) - 1): nodes[i].next = nodes[i + 1] print ...