2020 AMC 10B - Art of Problem Solving
artofproblemsolving.com › wiki › index2020 AMC 10B problems and solutions. The test was held on Wednesday, February 5, 2020. 2020 AMC 10B Problems; 2020 AMC 10B Answer Key. Problem 1; Problem 2; Problem 3; Problem 4; Problem 5; Problem 6; Problem 7; Problem 8; Problem 9; Problem 10; Problem 11; Problem 12; Problem 13; Problem 14; Problem 15; Problem 16; Problem 17; Problem 18 ...
2020 AMC 10B Exam Solutions - LIVE
live.poshenloh.com › amc10 › 2020BThis suggests: \[\begin{align*}4-4x^{2020} &\ge 0 \\ x^{2020} &\le 1\\ -1 \le x \le 1. \end{align*}\] Since \(x\) must be an integer for \(y\) to be an integer, this gives us three \(x\) values, each with either one or two corresponding \(y\) values. With this, we have the following four solutions: \[(-1,1)\] \[(0,0)\] \[(0,2)\] \[(1,1)\]